8k-24/k^2-10K=4/k+5/k-10

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Solution for 8k-24/k^2-10K=4/k+5/k-10 equation: 


D( x )

k^2 = 0

k^2 = 0

k^2 = 0

k^2 = 0

x naleu017Cy do R

x belongs to the empty set

8*k-(10*K)-(24/(k^2)) = 4/k+5/k-10

x belongs to the empty set

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